Calculates the inverse of the standard normal cumulative distribution.
NORM.S.INV(probability)
probability is required, and is the probability associated with the standard normal distribution (a value between 0 and 1).
Example:
If probability contains 0.95:
NORM.S.INV(0.95)
returns 1.644853627
probability:
Result:
Let's imagine a company that manufactures widgets and wants to ensure that the widgets meet specific weight requirements. The company knows that the weight of the widgets follows a normal distribution with a mean of 50 grams and a standard deviation of 2 grams.
The company wants to set a tolerance for the widget weight, such that only 1% of the widgets will be rejected for being too light.
They can use the NORM.S.INV function to find the minimum weight a widget can be and still be in the acceptable range.
Here is a step-by-step example using a table:
Step 1: Find the z-score for the lower 1% tail of the standard normal distribution. We want to find the z-score that corresponds to a cumulative probability of 0.01.
Probability | NORM.S.INV(Probability) | Description | ||
|---|---|---|---|---|
A | B | C | ||
1 | 0.01 | -2.326 | This is the z-score below which 1% of the data falls. |
The NORM.S.INV(0.01) function returns -2.326. This means that a z-score of -2.326 is the cutoff point for the lowest 1% of the data in a standard normal distribution.
Step 2: Convert the z-score to the actual weight using the formula: Weight = Mean + (z-score * Standard Deviation)
Variable | Value | ||
|---|---|---|---|
A | B | ||
1 | Mean | 50 grams | |
2 | Standard Deviation | 2 grams | |
3 | z-score | -2.326 |
Step 3: Calculate the minimum weight: Weight = 50 + (-2.326 * 2) = 50 - 4.652 = 45.348 grams
Conclusion: The company should set the minimum acceptable weight for a widget at 45.348 grams. Any widget weighing less than this amount will be rejected, ensuring that only 1% of the total production is discarded for being too light.
Minimum weight:
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